[SimonTheDriller]

So basically i am coding the program to display 5 temperatures , and the program will be able to display out the readings that the user enter and display out the average temperature as well .

But after writing out the codes , i encounter a tiny problem and i hope some pro can help to enlighten me out .



Basically , i wanna get rid of the last " , "

#include <iostream>
using namespace std;

void entry(double temp[]);
void display(double temp[]);
double avg_Temp(double temp[]);

int main()
{
double temp[5];
double average;
cout << "Room Temperature Analysis" << endl;
cout << "=========================" << endl<<endl;
entry(temp); // Call function to allow user to enter the readings
display(temp);
average = avg_Temp(temp);
cout << endl << endl << "Average temperature is : " << average ;


return 0;
}

// Your functions here

void entry(double temp[])
{
int i ;
for (i=0;i<5;i++)
{
cout << "Enter temperature : " ;
cin >> temp[i];
}
return;
}

void display(double temp[])
{
int i ;
cout << endl;
cout << "You have entered the following readings: " ;
for (i=0;i<5;i++)
{
cout << temp[i] << " , " ;
}
return;
}

double avg_Temp(double temp[])
{
int i ;
double sum = 0 , ave ;
for (i=0;i<5;i++)
{
sum = sum + temp[i] ;
}
ave = sum / 5.0 ;
return ave ;
}

[enriel]

You can simply edit your for statement in your display function

for (i=0;i<5;i++)
{
cout << temp[i] << " , " ;
}

use an if statement with a break function.

It should come out as:

for (i=0;i<5;i++)
{
    cout <<  temp[i];
    if (i == 4)
       break;
    cout << ",";
}

[sabe]

int i;
for (i=0;i<5;i++)
{
    cout << temp[i];
    if (i < 4)
        cout << ", ";
}

But you should avoid declaring your i outside if its just used for the loop.

Do this instead:

for (int i=0; i<5; i++)
{
    cout << temp[i];
    if (i < 4)
        cout << ", ";
}

[SimonTheDriller]

Originally Posted by sabe

[code]

But you should avoid declaring your i outside if its just used for the loop.

Do this instead:

for (int i=0; i<5; i++)
{
    cout << temp[i];
    if (i < 4)
        cout << ", ";
}

but like this the computer will not know whether "i" is a int , double , char wor...

Apart from that , since its a local variable , it would not affect anything outside that function ba .

By the way , Thank You both for your help , , i always encounter problem when it come to displaying out the thingy LOL T.T , guess i still got a long way to go ...

[universe]

Originally Posted by SimonTheDriller

but like this the computer will not know whether "i" is a int , double , char wor...

Apart from that , since its a local variable , it would not affect anything outside that function ba .

By the way , Thank You both for your help , , i always encounter problem when it come to displaying out the thingy LOL T.T , guess i still got a long way to go ...

within the for loop, i is a int. the compiler will know

[LiM]

for (i=0;i<4;i++)
{
cout << temp[i] << " , " ;
}

cout << temp[5] << " . ";

[Dreamslacker]

#include <iostream>
using namespace std;

void entry(double temp[]);
void display(double temp[]);
double avg_Temp(double temp[]);

int main()
{
  double temp[5];
  cout << "Room Temperature Analysis" << endl;
  cout << "=========================" << endl << endl;
  entry(temp); // Call function to allow user to enter the readings
  cout << endl;
  display(temp);
  cout << endl << endl << "Average temperature is : " << avg_Temp(temp);
  return 0;
}

// Your functions here

void entry(double temp[])
{
  int i=0;
  do {
    cout << "Enter temperature : " ;
    cin >> temp[i++];
  } while (i<=5);
  return;
}

void display(double temp[])
{
  int i=0;
  do {
    cout << "You have entered the following readings: " ;
    cout << temp[i++] << ", " ;
  } while (i<5);
  cout << temp[i];
  return;
}

double avg_Temp(double temp[])
{
  double sum = 0;
  for (int i=0;i<5;i++)  sum += temp[i] ;
  return (sum/5.0);
}

Evidently, I'm truely bored..